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during a ballistics test a bullet is fired into a thick gel to bring it to a stop. a 5.5-g bullet traveling at 325 m>s is brought to a stop in the gel by an average force of 550 n. what amount of time is needed for the bullet to come to rest?



Answer :

Eduard22sly

The time needed for the bullet to come to rest, given that it was travelling at 325 m/s is 3.25×10⁻³ s

How do I determine the time needed for the bullet to stop?

We'll begin by obtaining the deceleration of the bullet. This is shown below:

  • Mass (m) = 5.5 g = 5.5 / 1000 = 0.0055 Kg
  • Force (F) = -550 N
  • Deceleration (a) =? 5.71×10¹⁴

F = ma

-550 = 0.0055 × a

Divide both sides by 0.0055

a = -550 / 0.0055

a = -100000 m/s²

Finally, we shatll determine the time needed for the bullet to come to rest. Detail below:

  • Initial velocity (u) = 325 m/s
  • Deceleration (a) = -100000 m/s²
  • Final velocity (v) = 0 m/s
  • Time (t) =?

a = (v - u) / t

-100000 = (0 - 325) / t

-100000 = -325 / t

Cross multiply

-100000 × t = -3

Divide both sides by -100000

t = -325 / -100000

t = 3.25×10⁻³ s

Thus, we can say that the time needed is 3.25×10⁻³ s

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