Answer :
(a) The acceleration of the car beforeit comes to stop is 40/3 m/s² or 13.33 m/s² (b) The time it takes the car to stop is 1.5 s
What is acceleration?
This can be defined as the rate of change of velocity.
(a) To calculate the acceleration of the car, we use the formula below.
Fromula:
- v² = u²+2as......... Equation 1
Where:
- v = Final velocity = 0 m/s
- u = Initial velocity = 20 m/s
- s = Distance = 15 m
- a = Acceleration = ?
Substitute into equation 1 and solve for a
- 0² = 20²+2×15×a
- 0-400 = 30a
- 30a = -400
- a = -400.30
- a = -40/3 or -13.33 m/s²
(b) To calculate the time it takes the car to stop, we use the formula below.
- t = (v-u)/a
- t = (0-20)/(-40/3)
- t = 1.5 s
Hence, the acceleration of the car is -40/3 m/s² and the time it takes the car to stop is 1.5 s
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