Answer:
138° (nearest degree)
Step-by-step explanation:
Bearing: The angle (in degrees) measured clockwise from north.
The given scenario can be modelled as a right triangle (see attachment).
Therefore, the bearing is 90° + θ (shown in green on the attached diagram).
To find angle θ, use the cosine trigonometric ratio:
[tex]\implies \cos{\theta}=\dfrac{A}{H}[/tex]
[tex]\implies \cos{\theta}=\dfrac{624}{927}[/tex]
[tex]\implies \theta=\cos^{-1}\left(\dfrac{624}{927}\right)[/tex]
[tex]\implies \theta=47.69018863...[/tex]
[tex]\implies \theta=48^{\circ}\; \; \sf (nearest\;degree)[/tex]
Therefore, the bearing of the drawbridge from the tower is:
[tex]\begin{aligned}\implies \sf Bearing&=90^{\circ}+\theta\\&=90^{\circ}+48^{\circ}\\&=138^{\circ} \end{aligned}[/tex]
