If f(x)f(x) is an exponential function where f(4)=25f(4)=25 and f(11)=19f(11)=19, then find the value of f(18)f(18), to the nearest hundredth



Answer :

The value of the exponential function, f(x), when x = 18 is 14.44

What is an exponential function?

An exponential function is a function that consists of a constant term that has an index of the argument of the function, or in which the argument of the function is an index of a constant.

The general form of an exponential function is presented as follows;

  • f(x) = a·bˣ + k

The value of f(0) is left out in the information, therefore, where k = 0, we get;

f(x) = a·bˣ

From the question, we get;

f(4) = 25, therefore;

f(4) = 25 = a·b⁴

f(11) = 19, therefore;

f(11) = 19 = a·b¹¹

f(4)/f(11) = 25/19 = a·b⁴/(a·b¹¹) = b⁻⁷

b⁷ = 19/25

b¹⁸ = b⁷⁺¹¹ = b⁷ × b¹¹

b¹¹ = 19/a

f(18) = a·b¹⁸ = a × b⁷ × b¹¹ = a × b⁷ × b¹¹ = a × (19/25) × 19/a = 19²/25

f(18) = 19²/25

f(18) = 361/25 = 14,44

Learn more about exponential functions here:

https://brainly.com/question/11534388

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