Answer :
The concentration of the solution after it has been electrolyzed is 5.84 M.
How to find the concentration after electrolization?
Either an oxidation process, in which electrons are lost, or a reduction reaction, in which electrons are gained, is a half-cell reaction. The processes take place in an electrochemical cell where the electrons are consumed at the cathode during reduction and lost at the anode during oxidation.
Galvanic and voltaic cells, in which electrons move from the anode to the cathode through an electrolyte to create an electromotive force, can benefit from half-cell processes (EMF). Oxidation-reduction On metal surfaces, half-cell reactions can also happen and result in corrosion.
The chemical equation of half-cell is :
Cu2+ + 2e- -> Cu
We know that
W= [tex]\frac{E}{F}[/tex] x it
W=[tex]\frac{M}{n_{f} }[/tex] x [tex]\frac{it}{F}[/tex]
[tex]\frac{W}{M}[/tex] = [tex]\frac{i.t}{n_{f} F }[/tex]
n = [tex]\frac{1.55 X (15.27 X 60X60)}{2X96500}[/tex]
n = 0.441
So, molarity [tex]\frac{0.441}{1}[/tex]= 0.441
Therefore, Remaining concentration = 6.28 - 0.441 = 5.84
To learn more about half-cell reaction , click on link below
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