Answered

Dinitrogen pentoxide decomposes to form nitrogen dioxide oxygen, following the equation 2N2O5 >4NO2 +O2. At a certain timepoint, N2O5 is being consumed at a rate of 0. 1 M/s. What's the rate production of NO2 and )2 at the same timepoint?



Answer :

Rate of production of NO₂ = 0.2 M/

Rate of production of O₂ = 0.05 M/s

Given

The rate of N₂O₅ (dinitrogen pentoxide): 0.1 M/s

Reaction

2N₂O₅⇒4NO₂+O₂

Required

The rate of production of NO₂ and O₂ at the same time point

Rate of disappearance of N₂O₅ = reaction rate x coefficient of N₂O₅

0.1 M/s=reaction rate x 2

reaction rate = 0.05 M/s

The rate of production of NO₂=

Rate of production of NO₂ = reaction rate x coefficient of NO₂

Rate of production of NO₂ = 0.05 M/s x 4

Rate of production of NO₂ = 0.2 M/s

Rate of production of O₂ = reaction rate x coefficient of O₂

Rate of production of O₂ = 0.05 M/s x 1

Rate of production of O₂ = 0.05 M/s

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