Answer :

the mole percent of oxygen be in the diving gas for the partial pressure of oxygen in the mixture to be 0.21 atm , the same as in air at 1 atm is 2.52%

Atm 8.32 is the total pressure.

0.21 atm is the partial pressure of oxygen gas.

The relationship between partial pressure, total pressure, and mole fraction is depicted here.

partial oxygen pressure Total pressure x Mole percent of oxygen -

Calculate the gas's mole fraction of oxygen.

0.21 atm 8.32 x Mole fraction

Mole fraction = 0.21/8.32 = 0.0252

As illustrated below, determine the mole percent of the gas. Mole percent is equal to the mole fraction divided by 100, which is 0.0252 times 100 and 2.52% respectively.

As a result, oxygen's mole percent is 2.52%.

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