nitrogen gas at a pressure of 1.37 atm and a temperature of 315 k occupies 15.9 l of volume. calculate the temperature in degrees celsius when the pressure is changed to 1.65 atm and the volume to 3.24 l.



Answer :

Nitrogen is a drab fueloline or a liquid below pressure. It is the primary thing of air ,the temperature in degrees when the pressure is changed to 1.65 atm and the volume to 3.24 l is -195.9°C.

WE know.

  • PV = nRT
  • P = Pressure, V = Volume, n = Number of moles, R = Rygberg constant, T = Temperature
  • Case 1
  • PV = nRT
  • P = 1.37 atm, T = 315 K, V = 15.nine L, R = 0.0821 atm L/mol K
  • = 1.37X15.9= nX0.0821X315
  • n = 21.783/25.861
  • n = 0.8423 moles
  • Now we were given the Number of moles of Nitrogen fueloline, we practice ths cost in case 2 to get the Temperature.
  • Case 2
  • PV = nRT
  • P = 1.65 atm, T = ?? , V = 3.24 L, R = 0.0821 atm L/mol K, n = 0.8423 moles
  • 1.65X3.24 = 0.8432X0.0821XT
  • T = 5.346/0.0692
  • T = 77.25 K = (77.25-273.15) °c = -195.9°C.

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