Answer :
The volume of HCl needed will be 0.003 ml
6HCl + 2Al --------> 2AlCl3 + 3H2
The first thing we need to do is to determine the number of moles of HCl that are reacting.
Molarity = moles / volume of solution
Moles = given mass/molar mass = 0.0357 g/26.98 g
Moles = 0.001 moles
0.5 M = 0.001 mol/volume of solution
Volume = 0.02 ml
Now, we can determine the volume of HCl that will be needed to react with 0.5 moles of HCl by using the balanced equation.
0.5 moles x (2 mol Al/6 mol HCl) x (0.02/1)
= 0.003 ml
Hence, volume of HCl will be 0.003 ml
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