Costs for standard veterinary services at a local animal hospital follow a normal distribution with a mean of $89 and a standard deviation of $24. What is the probability that one bill for veterinary services costs between $53 and $125?.

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16-11-2022
Mathematics

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Costs for standard veterinary services at a local animal hospital follow a normal distribution with a mean of $89 and a standard deviation of $24. What is the probability that one bill for veterinary services costs between $53 and $125?.

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qwterabite qwterabite · Answer 1 · 2022-11-25T09:24:29-05:00

The probability that one bill for veterinary services costs between $53 and $125 is 0.866383

The probability that one bill for veterinary services costs between $42 and $133 will be given as follows P(53<x<125), Since the formula for calculating the z score is

z=(x-μ)/σ, where μ is the mean, σ is the standard deviation

since we are provided with means of $89 and a standard deviation of $24.So the z score will be :

for x = 53, z=(53-89)/24= -1.5

Therefore the probability P(x<53) is 0.066807

Again for x = $125, x=(125-88)/24=1.54

Therefore , the probabiltiy P(x<125) is 0.93319

The probability that one bill for veterinary services costs between $53 and $125, P(53<x<125) is :

=0.93319- 0.066807

=0.866383

To know more about probability refer to the link https://brainly.com/question/11234923?referrer=searchResults.

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