Complete Question:
The perimeter of a rectangular painting is 332 centimeters. if the length of the painting is 92 centimeters, what is its width?
If the length and perimeter of the painting are 92 cm and 332 cm, then the width of the rectangular painting is 74 cm.
Given Parameters :
Length of the painting (l) = 92 cm
The perimeter of the painting (b) = 332 cm
The perimeter of a rectangle is given by
P = 2 (l + b)
Putting the values in the formula, we get:
332 = 2 (92 + b)
332 = 184 + 2b
2b = 332 - 184 = 148
2b = 148
b = 148/2 = 74 cm
Thus, the width of the rectangular painting is 74 cm.
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