The equation of the line that is passing through the point (4,−17) and is perpendicular to y=x/7−3 is 7x -y = -30.
The line is passing through the point (4,-17) and is perpendicular to the line y = x/7-3
Now, the slope of the given line y = x/7-3 is,
M = 1/7
If the other line is perpendicular to it and has slope m, then the, we can write,
Mm = -1
So, putting values,
(1/7)m = -1
m = -7
Now, we have the slope m = -7 of the line and the point (4,-17) of the line,
So, the equation of the line will be,
m = [y-(-17)]/[x-4]
-7 = y+17/x-4
7x+47 = y+17
7x -y = -30
So, the equation of line is 7x -y = -30.
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