a rectangular box with a square base, an open top, and a volume of 32,000 cm3 is to be made. what is the minimum surface area for the box? enter only the minimum surface area, and do not include units in your answer.



Answer :

Using the Minimization of Area,

The dimensions of rectangular box are 20 and 40.

We have given that,

Volume of rectangular box = 32,000cm³

Assume b is the side of square base and h is the height of the box.

The formula to find the volume is equal to product of area of base and height

V = b²h

=> h = V/b² --(1)

The formula for the surface area is

A = b×b + 2b×h +2b×h = b² + 4bh

using equation (1) we get,

=> A = b² + 4V/b

differentiating Area (A) with respect to b

to find the minima and putting dV/db = 0

dA/db = 2b - 4V/b²

=> 2b - 4V/b² = 0

=> b³ = 4V/2

Plunging the value of volume in above equation we get,

b³ = 4 (32000)/2

=> b = 40 and

h = 32000/ 40×40 = 20

Thus , the dimensions of the rectangular box are 40 and 20.

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