Suppose a 95% confidence interval for the average amount of weight loss on a diet program for males is between 13. 4 and 18. 3 pounds. These results were based on a sample of 42 male participants who were deemed to be overweight at the start of the 4-month study. What is the standard error of the sample mean?.



Answer :

The standard error of the sample mean is 1.213

How to calculate the standard error of the sample mean?

Given,

c = 95% = 0.95

n = 42

lower limit = 13.4

upper limit = 18.3

Since standard deviation population is unknown, we use this formula to calculate standard error.

standard error = margin of error / [tex]t_{\alpha/2,d.f.}[/tex]

First, we calculate the t distribution value

[tex]t_{\alpha/2,d.f.}[/tex] = [tex]t_{(1-c)/2,n-1}[/tex]

= [tex]t_{(1-0.95)/2,42-1}[/tex]

= [tex]t_{0.025,41}[/tex]

To find the value use t table. So, [tex]t_{0.025,41}[/tex] = 2.0195

Next, we calculate the margin of error

margin of error = (upper limit - lower limit)/2

= (18.3 - 13.4)/2

= 4.9/2

= 2.45

Now, we can calculate the standard error. So,

standard error = 2.45 / 2.0195

= 1.213

Thus, the standard error of the sample mean is 1.213

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