Answer :
The velocity flow field is irrotational and the conservation of mass is preserved.
Irrotational flow for a two-dimensional velocity field happens when
[tex]\frac{dv}{dx} \:-\: \frac{du}{dy} \:=\: 0[/tex]
Conservation of mass for an incompressible happens when
[tex]\frac{du}{dx} \:+\: \frac{dv}{dy} \:=\: 0[/tex]
Perimeter
- u = y² - x (1+x)
u = y² - x - x² - v = y (2x + 1)
v = 2xy + y
Calculate the derivate in each function.
- [tex]\frac{du}{dx} = 0 - 1 - 2x = - 2x - 1[/tex]
- [tex]\frac{du}{dy} = 2y - 0 - 0 = 2y[/tex]
- [tex]\frac{dv}{dx} = 2y + 0 = 2y[/tex]
- [tex]\frac{du}{dy} = 2x + 1[/tex]
Checking the irrotational flow
[tex]\frac{dv}{dx} \:-\: \frac{du}{dy} \:=\: 2y - 2y = 0[/tex]
Checking conservation of mass for an incompressible
[tex]\frac{du}{dx} \:+\: \frac{dv}{dy} \:=\: - 2x - 1 + 2x + 1 = 2x - 2x + 1 - 1 = 0[/tex]
So the velocity flow field is irrotational and the conservation of mass is preserved.
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