Answer :
Using the concepts of momentum, we got that 13m/sec is the velocity of the ball after 2 sec if the distance the ball has rolled after t seconds is given by s(t) = 5t + 2t2 equation.
Velocity is defined as the derivative of displacement with respect to time
v= ds/dt
The given equation of distance is
s(t) = 5t + 2t² : distance that the ball has rolled after t seconds
v= 4 m/s : initial velocity
t= 2 s
Problem development
s(t) = 5t + 2t²
Using differentiability
v= ds/dt= 5 + 4t : velocity of the ball in function of the time
We replace t =2 s in the equation of velocity
v= 5 + 4(2)
=>v=5+8
=>v=13m/sec.
Hence, if a ball is given a push so that it has an initial velocity of 4 m/s down a certain inclined plane, and the distance it has rolled after t seconds is given by the following equation s(t) = 5t + 2t2,then the velocity of the ball after 2 sec is 13m/sec.
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(Complete question) is:
If a ball is given a push so that it has an initial velocity of 4 m/s down a certain inclined plane, then the distance it has rolled after t seconds is given by the following equation. s(t) = 5t + 2t2 . Find the velocity after 2 seconds.