. ****an elastic cord is 80. cm long when it is supporting a mass of 10. kg hanging from it at rest at rest. when an additional 4.0 kg is added, the cord is 82.5 cm long. hint: 4 kg stretches the cord 2.5 cm!!

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14-11-2022
Physics

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. ****an elastic cord is 80. cm long when it is supporting a mass of 10. kg hanging from it at rest at rest. when an additional 4.0 kg is added, the cord is 82.5 cm long. hint: 4 kg stretches the cord 2.5 cm!!

Answer :

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ayune ayune · Answer 1 · 2022-11-18T07:59:30-05:00

An elastic cord with natural length of 80 cm stretched to 82.5 cm when an additional 4 kg mass attached. The spring constant of the cord is 1600 N/m

According to the Hooke's Law, the force applied on a string is directly proportional to the length of extension ( or compression).

F = kx

Where:

F = applied force

k = spring constant

x = length of extension/compression

Data given from the problem:

Natural length = 80 cm

The length of stretch when an additional 4 kg mass added = 82.5

Hence,

x = length of extension = 82.5 - 80 = 2.5 cm = 2.5 x 10⁻² m

The force = 4 x 10 = 40 N

Hence, the spring constant:

k = F / x = 40 / (2.5 x 10⁻²) = 1600 N/m

Complete question:

an elastic cord is 80. cm long when it is supporting a mass of 10. kg hanging from it at rest at rest. when an additional 4.0 kg is added, the cord is 82.5 cm long. hint: 4 kg stretches the cord 2.5 cm!!

a. What is the spring constant of the cord?

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