Using the Time period formula for a Satellite,
the radius of orbit from earth center is 6.7590.
Time period : The satellite period is the time it takes for a satellite to make one orbit around the Earth, denoted by T. Therefore, T = distance traveled in 1 revolution/orbital velocity = 2πr/V.
We have the following information,
the Satellite revolves the earth twice in a day .
As we know,
mass of the earth(M) is 5.97 × 1024 kg
Gravitational constant (G)= 6.67 × 10-11 Nm²/kg²
The time taken to complete two rounds is a day. Time taken by the satellite in one alone will be cost to one by the day i.e., T = 24 hours
The time period of the satellite must be equal to
2T = 2×24×60×60 sec = 172800 sec.
According to Kepler's 3Rd law ,
T² = ( 4π²/GM )r³---(1)
where, T ---> time period
M --> mass of earth
G--> gravtional constant
r --> radius of orbit
putting all the values in above formula
(172800)² = ( 4×(3.14)²/(6.67 × 10-11 Nm²/kg²× 5.97 × 1024 kg))r³
=> r³ = (172800)²/96,720,640.93= 308.722
=> r = 6.75890 ~ 7
Hence, the radius of orbit is 6.75890
To learn more about Satellite motion around earth , refer:
https://brainly.com/question/1448749
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