The final velocity at the end of this time will be 200 [tex]m/s^{2}[/tex]
When any object is in free fall, then
The value of acceleration = g [tex]m/s^{2}[/tex] = 10 [tex]m/s^{2}[/tex]
The initial velocity (u) = 0 m/s
Let the final velocity (v) = v m/s
The mass of the object (m) = 10 kg
Time taken to reach the ground = 20 s
We will calculate the height (s) from which the object falls,
We employ the 2nd equation of motion since the object is under constant acceleration,
We have,
[tex]s = ut +\frac{1}{2} at^{2}[/tex]
Putting the values in the equation, we get
[tex]s = 0 +\frac{1}{2} *10 *20^{2} \\\\s = 2000[/tex]
Thus, the height is 2000 m
Now, we apply the third equation of motion,
[tex]v^{2} -u^{2} = 2as[/tex]
Putting all the values, we get,
[tex]v^{2} -0^{2} = 2*10*2000\\\\v^{2} = 40000\\\\v = 200[/tex]
Hence, the final velocity at the end of this time will be 200 [tex]m/s^{2}[/tex]
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