a 50 kg crate is pulled across the ice with a rope. a force of 100n is applied at some angle with the horizontal. the vertical component of the force in the rope is 40n. neglecting friction, calculate the acceleration of the crate and the upward force the ice exerts on the crate as it is pulled.

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14-11-2022
Physics

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a 50 kg crate is pulled across the ice with a rope. a force of 100n is applied at some angle with the horizontal. the vertical component of the force in the rope is 40n. neglecting friction, calculate the acceleration of the crate and the upward force the ice exerts on the crate as it is pulled.

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aditmarkas98 aditmarkas98 · Answer 1 · 2022-11-18T16:31:47-05:00

The acceleration of the crate is 1.83 m/s² and the upward force is 40 N.

We need to know about force to solve this problem. According to second Newton's Law, the force applied to an object will be proportional to mass and acceleration. Hence, it can be written as

F = m . a

where F is force, m is mass and a is acceleration

From the question above, we know that

Fy = 40 N

F = 100 N

m = 50 kg

Find the horizontal force

F² = Fy² + Fx²

100² = 40² + Fx²

Fx² = 100² - 40²

Fx² = 8400

Fx = 91.65 N

Find the acceleration of the crate

Fx = m . a

91.65 = 50 . a

a = 1.83 m/s²

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