question a toy doll and a toy robot are standing on a frictionless surface facing each other. the doll has a mass of 0.20 kg, and the robot has a mass of 0.30 kg. the robot pushes on the doll with a force of 0.30 n. the magnitude of the acceleration of the robot is



Answer :

The magnitude of the acceleration of the robot is  1 m/s².

Acceleration is the rate of change of the velocity of an item with appreciation to time. Accelerations are vector portions. The orientation of an item's acceleration is given by the orientation of the net pressure appearing on that object.

Calculation:-

mass of doll = 0.20 kg

mass of robot = 0.30 kg

Force on dall by robot = 0.30 N

acceleration on doll = mass of doll / force of robot

                                = 0.20 / 0.30

                                = 0.67 m/s²

Same force applied to the robot by Newton's third law of motion = 0.30 N

acceleration of the robot = mass of robot/force

                                         = 0.30 / 0.30

                                         = 1 m/s²

Acceleration is the charge at which velocity modifications with time, in terms of each speed and route. A factor or an object moving in a straight line is accelerated if it quickens or slows down. movement on a circle is extended despite the fact that the rate is consistent because the course is continually changing.

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