Answer :
a) For resonance this circuit should be resistive hence Xc = 30 ohm.
b) Total impedance = |2+30i=30i| = 2ohm.
c) Current=50mV/2=25mA.
d) |VL|=|Vc|=30*25mA=0.75V=750mV since impedance same and they are in series VR= 50mV.
e) Q=wL/R=w*L/R=30/2=15 since wL = 30ohm it is a high Q circuit.
f) Power disspated=i^2R = (25*25*10^(-6).)*2 = 1.25mJ.
The higher the Q the lower the energy loss rate and the slower the vibration damping. A pendulum suspended from high-quality bearings and oscillating in the air has a high Q, while a pendulum immersed in oil has a low Q. High-Q resonators have lower damping, so they oscillate or oscillate longer.
A circuit's figure of merit Q is the electrical energy stored in the circuit divided by the energy consumed in one cycle. The Q of a circuit is an important quantity in certain applications, such as in electromagnetic waveguides and radio frequency cavities.
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