Two approximations of the area of the region between the graph are
(9, 11)
Given;
To calculate two approximations of the area of the region between the graph of the function and the x-axis across the given interval, use the left and right endpoints and the specified number of rectangles. rectangles f(x) = 2x + 3, [0, 2], 4
The graph is positive and the width of each subinterval will be,
a = 0, b = 2, n = 4
Δx = b-a/n = 2-0/4
= 0.5
Now for different values;
x → f(x) = 2x+3
x₀ = 0 → f(x₀ ) = 2x+3 = 2(0)+3 = 3
x₁ = 0.5 → f(x₁) = 2x+3 = 2(0.5)+3 = 4
x₂ = 1.0 → f(x₂) = 2x2+3 = 2(1) +3 = 5
x₃ =1.5 → f(x₃) = 2x+3 = 2(1.5)+3 = 6
x₄ = 2 → f(x₄) = 2x+3 = 2(2)+3 = 7
The area by using the approximation using 4 approximating rectangles and right endpoints is given by,
A ≈ R₄ = ∑f(x) Δx = ( ƒ(x1)Δx + ƒ (x2)Δx+ ƒ (x3)Δx + ƒ (x4)Δx)
= 0.5 (4 + 5 + 6 + 7)
= 0.5 × 22
= 11
The area by using the approximation using 8 approximating rectangles and left endpoints is given by.
A ≈ L₄ = ∑f(x) Δx = ( ƒ(x0)Δx + ƒ (x1)Δx+ ƒ (x2)Δx + ƒ (x3)Δx)
= 0.5 (3 + 4 + 5 + 6)
= 0.5 × 18
=9
Thus, 9 < Area < 11.
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