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a spring with a spring constant of 8.0 n/m is initially compressed to 5.0 cm. the work done as it is compressed another 15 cm, to a total compression of 20 cm is: a. 0.85 j. b. 0.54 j. c. 0.25 j. d. 0.15 j. e. 0.09 j.



Answer :

When a spring with an initial compression of 5.0 cm is compressed by 0.15, a total compressed of 20 cm is achieved. as it is compressed another 15 cm, the work is completed. spring constant 8.0 n/m

The spring constant can be calculated using the spring constant. Springs that are more rigid are more likely to be challenging to stretch. Elastic substances make up springs. spring constant deforms when external forces are applied, but it returns to its original position once the force is removed. A linear elastic deformation has occurred with the spring. The relationship curve between force and displacement is linear.

A type of compressed spring that generates linear force is the spring.

Work completed, w = 0.5 k x - 0.5 ky

W= 1/2K (x^2 - y^2 )

W = 1/2 ( 8 ) / (20 * 10^ -2 ) ^2 - ( 5* 10 ^-2 ) ^2 J

W = 0.15 J

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