A 20 gram bullet traveling at 250m/s strikes a block of wood that weighs 2kg. With what velocity will the block and bullet move after the collision?.



Answer :

The conservation of momentum can be used to determine the final velocity. The block and bullet system's velocity after the collision will be 2.5 m/s.

For example, a circular path's direction is always perpendicular to a line from the point to the circle's center. A point always moves in a direction that is tangent to its path (a radius). Using the momentum principle,

Where,

= bullet weight, 20 g, or 0.2 kilogram

250 m/s is the bullet's speed before colliding.

= block weight = 2 kg

= velocity following impact =?

Fill out the formula with the values,

Therefore, the block and bullet system's velocity following the collision will be 2.5 m/s.

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