g if the standard deviation of the lifetimes of television tubes is estimated to be 100 h, how large a sample must we take in order to be (a) 95%, (b) 99%, and (c) 99.73% confident that the error in the estimated mean lifetime will not exceed 20 h?.



Answer :


So the of 95% is 19/24 and 99%is 33/40
And 34/40 means diffelction from mean value. That is

Given that the standard of life time is 100h
And life is not exceed by 20 h
So maximum life time will be 120 h
And minimum life time will be 80 h
So a) if he is 95 % confident than
P(x<20) is 100/120
=5/6
As he 95% confident than
5/6*95/100
5/6*19/20
19/24
B) 99%
So it will be equal to 5/6*99/100
33/40
C) 99.73
So it will be equal to 5/6*99.73/100
Approx
34/40

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