The flowrate of decreasing water is 3.98 cm/min after the water reaches 5cm of its height.
We need to know about the flowrate to solve this problem. The rate can be described as how much water flows in a unit of time. It can be represented by this equation
Q = V / t
where Q is flowrate, V is volume and t is time.
From the question above, the given parameters are
Inverted cone with
Q = 50 cm³/min
R = 4 cm
h = 5 cm
Hence, the rate of decreasing water is
Q = V / t
50 = A . h / t
50 = π . R² . h / t
50 = 22/7 . 4 . h / t
h/t = 3.98 cm/min
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