Answer :
The power that the brakes/friction produce to bring the car to rest in 3 seconds is 86,666.667 W
This is how it is works:
Mass = 1300 kg
Speed = 20 m/s
Time = 3 seconds
Power to stop the car = ?
We can use the formula of kinetic energy to solve this problem. Let's take a look:
K.E = ½ m × v²
K.E = ½ 1300 × 20²
K.E = 650 × 400
K.E = 260,000 J
We got the kinetic energy that valued 260,000 J but we do not finished yet. In the question, we should stop the car in 3 seconds then we should find the power produced by the brakes. Here it is:
Power = Work : Time
Power = 260,000 : 3
Power = 86,666.667 W
KINETIC ENERGY:
Kinetic energy refers to the energy of a body due to its motion. The kinetic energy can be calculated as follows:
K.E = ½ m × v²
Where :
- K.E = kinetic energy (J)
- m = mass (kg)
- v = velocity (m/s)
Learn more about kinetic energy https://brainly.com/question/25959744
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