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a car is accelerated from 30 mil/h to 55 mil/h during a period of 20 s. calculate the magnitude of the force exerted on the car to accelerate.



Answer :

The magnitude of the force exerted on the car to accelerate is 0.5588m N

We got some values here,

v[tex]_{0}[/tex] = 30 mil/h = 13,4112 m/s

v[tex]_{1}[/tex] = 55 mil/h = 24,5872 m/s

t = 20 s

First, we should find the acceleration of the car

a = v/t

a = v[tex]_{1}[/tex] - v[tex]_{0}[/tex] / t[tex]_{1}[/tex] - t[tex]_{0}[/tex]

a = 24.5872 - 13.4112 / 20 - 0

a = 11.176 / 20

a = 0.5588 m/s[tex]^{2}[/tex]

Now we got the amount of acceleration. We can found the force by the formula of: F = m.a but we are not given the mass value in the question. So, we can answer this question by this way

F = m.a

F = m × 0.5588 m/s[tex]^{2}[/tex]

F = 0.5588m N

What is acceleration?

Acceleration (a) is the change in velocity (Δv) over the change of time (Δt), represented by the equation a = Δv/Δt. This allows you to measure how quick velocity changes in meters per second squared (m/s[tex]^{2}[/tex]. Acceleration is also a vector quantity, so it includes both magnitude and direction.

Learn more about acceleration https://brainly.com/question/460763

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