Answer :
The moment inertia of the boxer's forearm is 0.43 kgm².
We need to know about torque to solve this problem. Torque is the rotational equivalent of linear force. It can be determined as
τ = F x r
where τ is torque, F is perpendicular force and r is radius.
Torque also depends on the moment inertia
τ = I . α
where I is inertia and α is angular acceleration.
From the question above, the given parameters are
F = 1975 N
r = 2.5 cm = 0.025 m
α = 115 rad/s²
Substitute the first equation with the second equation and we can calculate the inertia of the boxer's forearm
τ = τ
F x r = I . α
1975 . 0.025 = I . 115
I = 0.43 kgm²
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