Answer :
Meiosis I is a nuclear division that results in the creation of two nuclei. Meiosis I and Meiosis II cytokinesis result in the formation of TWO cells, each with a HAPLOID number of chromosomes.
Meiosis is a two-stage process in which the number of cells doubles but the number of chromosomes does not. Meiosis I is the initial division. As a result, each cell has half as many chromosomes. Meiosis II is the second division; unlike mitosis, it does not result in a reduction in the number of chromosomes.
Cytokinesis between Meiosis I and Meiosis II forms TWO cells each with a HAPLOID number of chromosomes.
The cells go through cytokinesis, the nuclear envelope forms, and the nucleoli reappear. Each cell with 46 chromatids divides into two cells with 23 chromosomes during meiosis II.
Meiosis II is NUCLEAR division which produces TWO nuclei in TWO cells for a total of FOUR nuclei.
The development of four daughter cells, each with four nuclei, marks the conclusion of meiosis II. Additionally, each of the four chromosomes has a haploid set, which means that they each contain 23 chromosomes.
Nuclear division during meiosis II results in the production of TWO nuclei in TWO cells, for a total of FOUR nuclei.
The development of four daughter cells, each with four nuclei, marks the conclusion of meiosis II. Additionally, each of the four chromosomes has a haploid set, which means that they each contain 23 chromosomes.
Cytokinesis after Meiosis II forms FOUR cells each containing a HAPLOID number of chromosomes.
The cells go through cytokinesis, the nuclear envelope forms, and the nucleoli reemerge. Each cell with 46 chromatids divides into two cells during meiosis II, each of which has 23 chromosomes.
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