Five lights, A, B, C, D, and E, are aligned in a row. The middle light is the midpoint of the segment between the second and fourth lights and also the midpoint of the segment between the first and last lights. Given: C is the midpoint of BD and AE. Prove: AB = DE
I need help writing the reason part of a two-column proof on this​



Answer :

Since C is mid - point of both BD and AE , therefore AB = DE .

Given : A , B , C , D and E are aligned in a row .

            C is the mid - point of BD and AE .

To prove : AB = DE .

Since , C is the mid - point of BD ,

⇒ BC = CD  ( 1 )

And since C is the mid - point of AE as well ,

⇒ AC = CE    ( 2 )

Subtracting ( 1 ) from ( 2 ) ,

AC - BC = CE - CD

AB = DE

Hence , proved AB = DE .

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