Since C is mid - point of both BD and AE , therefore AB = DE .
Given : A , B , C , D and E are aligned in a row .
C is the mid - point of BD and AE .
To prove : AB = DE .
Since , C is the mid - point of BD ,
⇒ BC = CD ( 1 )
And since C is the mid - point of AE as well ,
⇒ AC = CE ( 2 )
Subtracting ( 1 ) from ( 2 ) ,
AC - BC = CE - CD
AB = DE
Hence , proved AB = DE .
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