Answer :
The total energy of the international space station orbiting the earth is -μ/2a.
The total energy is the sum of kinetic energy and potential energy.
E = [tex]E_{k}[/tex] + [tex]E_{p}[/tex]
= v²/2 - μ/r
= -1/2 μ²/ h² (1-e²)
= -μ/2a
Here v = relative orbital velocity
r = orbital distance between the bodies
μ = G(m1 + m2) = the sum of the standard gravitational parameters of the bodies.
h = specific relative angular momentum in the sense of relative angular momentum.
e = orbital eccentricity
a = semi-major axis
Therefore we get the total energy is -μ/ 2a.
To know more about the total energy of the internal space refer to the link given below:
https://brainly.com/question/19466094
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