. a survey of first-time home buyers found that the sample mean annual income was $51,000. assume that the survey used a sample of 28 first-time home buyers and that the sample standard deviation was $1,200. compute and explain a 95% confidence interval estimate of the population mean.



Answer :

The 95% confidence interval estimate of the population mean is between $50,555.51 and $51.444.49.

Confidence interval is defined as the range of values where a parameter might fall at a given confidence level. It can be calculated using the formula below.

CI = μ ± z x (SD / √n)

where CI = confidence interval

μ = sample mean

z = found by using a z-score table

SD = sample standard deviation

n = sample size

At 95% confidence level, the area in each tail of the standard normal curve is 2.5, and the cumulative area up to the second tail is 97.5.

(100 - 95) / 2 = 2.5

100 - 2.5 = 97.5

Find 0.975 in the z-table to get the value of z.

At p = 0.95, z = 1.96

Plug in the values and solve for the confidence interval.

CI = μ ± z x (SD / √n)

CI = $51,000 ± 1.96 x ($1,200 / √28)

CI = $51,000 ± $444.49

CI = [$50,555.51, $51.444.49]

Learn more about confidence interval here: brainly.com/question/15905481

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