The current flowing through the light bulb is 9.6 Amperes.
According to the Ohm's Law, the potential difference or voltage across a conductor is directly proportional to the current to the current flowing in the conductor, so,
V ∝ I
V is voltage, I is current,
V = IR
Here, the voltage of the battery is 24V.
The resistance of the light bulb is 2.5 Ohms,
Now, putting values,
24 = 2.5I
I = 9.6 A.
So, the current flowing through the light bulb is 9.6A.
To know more about Ohm's law, visit,
https://brainly.com/question/14296509
#SPJ4