71.43 J of work is required, using an ideal Carnot refrigerator, to remove 1 j of heat energy from helium at 4 k and eject this heat to a room temperature (293 k) environment
coefficient of performance = T / ΔT
= 4 / 293 - 4 = 0.014
Qc (heat) = work * coefficient of performance
work = Qc / coefficient of performance
= 1 / 0.014 = 71.43 J
71.43 J of work is required
To learn more about Carnot refrigerator here :
https://brainly.com/question/13441103
#SPJ4