how much work is required, using an ideal carnot refrigerator, to remove 1 j of heat energy from helium at 4 k and eject this heat to a room temperature (293 k) environment?



Answer :

71.43 J of work is required, using an ideal Carnot refrigerator, to remove 1 j of heat energy from helium at 4 k and eject this heat to a room temperature (293 k) environment

coefficient of performance = T / ΔT

                                             = 4 / 293 - 4 = 0.014

Qc (heat) = work * coefficient of performance

work = Qc /  coefficient of performance

        = 1 / 0.014 = 71.43 J

71.43 J of work is required

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