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a 1.5m long dowel is pivoted about the end so that it is a pendulum of sorts - it can freely swing in a vertical plane. at the other end of the dowel is a brass weight having mass 1.5 kg. (the center of the brass weight is 1.5 m from the pivot point. when the rod is positioned in its swing such that its angle with the vertical is 22.5 degrees, what is the torque on the rod about the pivot due to the presence of the brass weight?



Answer :

The torque on the rod about the pivot due to the presence of the brass weight is 8.44 N.m.

What is torque?

The force that can cause an object to rotate along an axis is measured as torque. In linear kinematics, force is what drives an object's acceleration. Similar to this, an angular acceleration is brought on by torque. As a result, torque can be thought of as the rotational counterpart to force. The axis of rotation is a straight line about which an object rotates.

Given parameters:

Mass of the brass weight, m= 1.5 kg.

Length of the rod, l = 1.5 m.

Angle with the vertical; θ =22.5⁰.

We have to find, torque on the rod about the pivot due to the presence of the brass weight; ζ = ?

Force applied by the brass weight; F = mass × acceleration due to gravity  = 1.5 × 9.8 N =  14.7 N.

So, torque on the rod about the pivot due to the presence of the brass weight; ζ = Fl sinθ

= 14.7 × 1.5 × sin22.5° N.m

= 8.44 N.m.

Hence, the applied torque is 8.44 N.m.

Learn more about torque here:

https://brainly.com/question/6855614

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