Answer :
The speed of the aircraft relative to the ground is 606.9 km/h.
Solution:
x-y coordinate system:
x is positive east. Similarly, y is positive north.
Now let's decompose each vector into x-y
500 km/h due east = (500, 0)
120 km/h at 30 north of east
= (120cos(30), 120 x sin(30)
= (120 x [tex]\frac{\sqrt{3} }{2} , 120*\frac{1}{2}[/tex])
= (60 x [tex]\sqrt{3}[/tex], (60)
Adding the vectors.
= (500,0)+(60 x [tex]\sqrt{(3)}[/tex],(60)
= (500 + 60 x [tex]\sqrt{(3)}[/tex],60
= (500 + 60 x 1.73,60)
= (500 + 103.8,60)
= (603.8,60)
Returning back to polar form
Magnitude = [tex]\sqrt{603.923^{2}+60^{2} } = 606.9[/tex]
The speed of the aircraft relative to the ground is equal to the speed of the aircraft relative to the air plus the velocity of the air relative to the ground. In other words, it neither moves closer nor farther away from you. They move at 80 km/h relative to the observer next to the track. They do not move relative to the textbook.
Learn more about The aircraft relative here:-https://brainly.com/question/14931557
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