The stone reach in 3 second and with velocity 15m/s.
To find time
s = 1/2 a [tex]t^{2}[/tex]
s = distance, given = 45 meter
a = acceleration, given = 10 m/[tex]s^{2}[/tex]
Put these values in formula to get time, s = 1/2 a [tex]t^{2}[/tex]
t = 3 s
Now, to find velocity.
v = s/t
v = 45/3
v = 15 m/s
Therefore, the stone reach in 3 second and with velocity 15m/s.
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