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a 416-m long train is moving on a straight track with a speed of 83.2 km/hr. upon reaching a roadway crossing, the engineer engages the brakes. sometime later the caboose passes the crossing with a speed of 18.0 km/hr. determine the length of time (in seconds) that the train blocks the crossing. assume a constant acceleration and disregard the length of the crossing.



Answer :

The length of time (in seconds) that the train blocks the crossing are 29.15 s.

Velocity is defined as the trade in position or displacement (∆x) divided by the time durations (∆t) wherein the displacement takes place. The common velocity can be effective or negative depending upon the sign of the displacement. The SI unit of average velocity is meters per second (m/s or ms-1).

Average velocity is calculated by means of dividing your displacement (a vector pointing out of your initial role in your final position) through the entire time; the average pace is calculated by way of dividing the overall distance you traveled by means of the total time.

Calculation:-

the average velocity =(82.4+16.4)/2

                             =49.4 km/h

the distance travelled =length of the train =400 m=0.4km

 time taken =distance /average speed

                =0.4/49.4

                 =0.00809 h

                  =29.15 s

Learn more about velocity here:-brainly.com/question/1844960

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