an object is revolving uniformly in a horizontal circle of radius 1.0 m with a speed of 1.0 m/s, calculate its centripetal acceleration. g



Answer :

The centripetal acceleration is 1 m/s^2 .

Centripetal force is applied when there is a object revolving in circular path. This path is applied in the opposite direction of the center of the circular path and also this would be perpendicular to the velocity direction.

The value of centripetal force is

Fc = [tex]\frac{mv^{2} }{r}[/tex]

where m is the mass of the object

v is the velocity and r is the radius of the object.

Now as we know that

F = ma

where a is the acceleration

so we can write that

a = v^2/r

putting the values, we get

a = 1^2/1

a = 1/1

a = 1 m/s^2

Hence the centripetal acceleration is 1 m/s^2.

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