a cube made of platinum (pt) has an edge length of 1.10 cm. the density of pt is 21.45 g/cm3. (a) calculate the number of pt atoms in the cube.



Answer :

The number of platinum (pt) atoms in the cube is 6.6* 10⁻²² .

Number of atoms in a molecule of given weight can be calculated by dividing the total mass of molecule by mass of single atom .

we have provided the following informations,

length of edge = 1.10 cm

density of platinum (pt) = 21.45 g/cm³

Mass of single platinum (pt) atom

= 3.2×10⁻²² g

For calculating the number of platinum atoms present in cube first we find out the amount of platinum present in grams.

density of atom = mass of atom (grams) / Volume of solution(cm³).

21.45 g/cm³ = mass of pt in grams /1.0cm³

mass of platinum present in grams

=21.45 g

Using the Atomicity, number of atoms present is

21.45 g / 3.2 × 10⁻²²g = 6.6 × 10⁻²²platinum atoms.

Therefore, the number of platinum (pt) atoms is 6.6× 10⁻²² .

To learn more about Number of Atoms, refer :

https://brainly.com/question/21428446

#SPJ4

Other Questions