a race car entering the curved part at the Daytona 500 drops its speed from 85.0m/s to 80.0 m/s in 2.0s. if the radius of the curved part of the track is 316.0 m, calculate the total acceleration of the race car at the beginning and ending of reduction of speed

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09-11-2022
Physics

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a race car entering the curved part at the Daytona 500 drops its speed from 85.0m/s to 80.0 m/s in 2.0s. if the radius of the curved part of the track is 316.0 m, calculate the total acceleration of the race car at the beginning and ending of reduction of speed

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smecloudbird17 smecloudbird17 · Answer 1 · 2022-11-22T04:04:38-05:00

A race car entering the curved part at the Daytona 500 drops its speed from 85m/s to 80m/s in 2s. If the radius of the curved part of the track is 316m, the total acceleration of the race car at the beginning is 22.86m/s² and at the ending of reduction of speed is 20.25m/s².

The car is moving in the curved part and hence possesses centripetal acceleration. It is given by the formula, a=v²/r

where, a is centripetal acceleration in m/s²

v is velocity in m/s

r is radius in metres

It is given that the velocity of the car in the beginning is 85m/s (v₁) and the velocity of the car in the ending is 80m/s (v₂).

Now, let us find out the acceleration of the car in the beginning (a₁) and in the ending (a₂).

a₁=(v₁)²/r = (85)²/316 = 22.86m/s²

a₂=(v₂)²/r = (80)²/316 = 20.25m/s²

Thus, the total acceleration of the race car at the beginning and at the ending of reduction of speed are 22.86m/s² and 20.25m/s² respectively.

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