The amount of stock solution that would be needed to prepare the required solution would be 0.06 L.
The problem can be solved using the dilution principle. According to this principle, before and after diluting a particular solution, the number of moles of solutes in the solution must remain the same.
The dilution principle is expressed as an equation as shown below:
[tex]m_1v_1[/tex] = [tex]m_2v_2[/tex]
Where:
[tex]m_1[/tex] = molarity before dilution (in this case, 13%)
[tex]v_1[/tex] = volume before dilution (what we want to determine)
[tex]m_2[/tex] = molarity after dilution (in this case, 0.5%)
[tex]v_2[/tex] = volume after dilution ( in this case, 1.6 L)
Using the provided information, the volume of the stock solution to be taken can be calculated as follows:
[tex]v_1[/tex] = [tex]m_2v_2[/tex]/[tex]m_1[/tex]
= 0.5 x 1.6/13
= 0.06 L
In other words, 0.06 L of the stock solution would be required. This volume will be diluted to the 1.6 L mark with water in order to have the desired solution.
More on dilution can be found here: https://brainly.com/question/21323871
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