The amount of the salts left undissolved at 40 °C is Lead II nitrate = 300 g and Potassium chloride = 100 g and Potassium dichromate = 0 g.
We are aware that the mass of a solute that may dissolve at a specific temperature is related to the solubility. The absorption is temperature dependant, it must be said.
Let's consider how much of each salt would absorb at 40 °C;
Pb(NO3)₂ : 0.0g
KCl : 100.0g
K₂Cr₂O₇ : 300.0g
For any salt, we may calculate the amount that can be dissolved at 40 °C by dissolving 500 g and subtracting its solubility at that temperature.
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The complete question is-
For each salt, determine how much will remain undissolved if 500 g is mixed into a liter of pure water at 40 °C. One significant figure is sufficient in each answer.
Pb(NO3)₂:
KCI:
K₂Cr₂O7: