Answer :
The constants that we have to multiply to eliminate one variable from the system are 12 and 5.
The equations are
5x+13y = 232
12x + 7y = 218
Here we can cancel both x term and y terms, lets choose x terms and apply the elimination method
The coefficient of x in first equation is 5 and 12 in second equation
We have to make it same
Prime factorization
5 = 5×1
12 = 2×2×3
LCM (5, 12 ) = 2×2×3×5 = 60
Multiply the first equation by 12 and second equation by 5
60x + 156y = 2784
60x + 35y = 1090
Subtract equation 2 from equation 1
121y = 1694
Here we have eliminated x term
Hence, the constants that we have to multiply to eliminate one variable from the system are 12 and 5.
The complete question is:
Which constants can be multiplied by the equations so one variable will be eliminated when the systems are added together? 5x + 13y = 232
12x + 7y = 218
Learn more about elimination method here
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