Answer :

  • A ball of mass 0.800 kg is carefully balanced on a shelf that is 2.50 m above the ground. The gravitational potential energy is
  • When an item is placed at a height 'h' above the ground, its potential energy is given as
  • [tex]P.E. = mg*h[/tex]
  • where the acceleration brought on by gravity is equal to [tex]9.8 m/s2[/tex][tex]9.8 m/s^2[/tex].
  • To determine the solution, substitute the numbers.
  • The conservation of energy principle mandates that all potential energy be transformed into kinetic energy when the ball hits the ground.
  • Consequently, it is K.E = P.E right before impact (on the shelf)

         K.E. is supplied by

        [tex]K.E. = 1/2. mv2[/tex]

         [tex]KE = PE[/tex] because

         [tex]1/2*mv2 = mg*h[/tex]

         So,[tex]v = \sqrt{(2g/m)}[/tex]

What is potential energy?

  • An item may store energy according to its location, as we all know.
  • In the instance of a bow and arrow, the bow stores some energy as it is drawn, and this energy is what gives the arrow its kinetic energy when it is released.
  • Similar to this, a spring accumulates energy as it is moved away from its equilibrium state, which we can notice by the tension our hands experience when we stretch it.
  • Potential energy is a type of energy that is created when anything changes position or condition.

However, Let's study the definition of potential energy and its formula before moving on to instances and the potential energy unit.

To learn more about Potential energy do follow

https://brainly.com/question/14427111

#SPJ4

Other Questions