Answer :
Jim needs a score of 115 on his third test to keep an average of 89 or greater.
A mean represents the average value among a set of values.
Mean = (sum of all values)/(total number of values)
In other words, mean is the value assigned to each member of set after fair distribution. It means that if a set of n values has a mean of x, we can assume the set to be 'x' value recurring n times over the sample.
In this case, we have 3 test results: 83, 69 & x, where x is the unknown result of 3rd test. Our required minimum average/mean is 89.
Substituting these in our formula for mean, we get:
[tex]89=\frac{83+69+x}{3} \\89*3=152+x\\x=267-152=115[/tex]
Thus, 115 is our required test result for maintaining average of minimum 89.
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