The numbers 0, 2, and 5 can be repeated any number of times to create 16 three-digit numbers.
Given that,
As many three-digit numbers as you can must be written. Only the numerals 0, 2, and 5 may be used in your replies, although you may repeat digits.
This is a problem on Permutations
Permutation is the different ways that a set of elements can be arranged, either all at once or part of them at a time. There are two alternative arrangements, AB and BA, for instance, if we have two elements, A and B.
Repeating number permutation
= 3³ - 11(as one of the digit is Zero "0")
= 3 × 3 × 3 - 11
= 16
Let me list each result one by one.
222, 205, 250, 255, 225, 252, 220, 202.
502, 520, 552, 525, 555, 522, 550, 505.
Thus, there are 16 three-digit integers that may be constructed by the numbers 0,2, and 5 with any digit repeated.
Learn more about permutation :
brainly.com/question/1216161
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