Answer :
The magnitude of the velocity of the bar at an instant when the induced current in the circuit is counterclockwise and equal to 1.73 A is 24.62 m / s
I = B l v / R
I = Induced current
B = Magnetic field
l = Length of bar
v = Velocity
R = Resistance
I = 1.73 A
B = 1.34 T
l = 0.293 m
R = 5.55 Ω
v = I R / B l
v = ( 1.73 * 5.55 ) / ( 1.34 * 0.293 )
v = 9.6 / 0.39
v = 24.62 m / s
Therefore, the the magnitude of the velocity of the bar is 24.62 m / s
The given question is incomplete. The complete question is :
A 0.293m -long bar moves on parallel rails that are connected through a 5.55 Ω resistor, as shown in the following figure (Figure 1) , so the apparatus makes a complete circuit. You can ignore the resistance of the bar and rails. The circuit is in a uniform magnetic field 1.34T that is directed into the plane of the figure. At an instant when the induced current in the circuit is counterclockwise and equal to 1.73 A, what is the magnitude of the velocity of the bar?
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